Distributive Property Kya Hai? | Class 8 Maths Book 1 Ch 6

πŸ“˜ Class 8 Β· Ganita Prakash Book 1Ch 6 Β· We Distribute, Yet Things MultiplyPost 1 / 7⏱ 25–30 min
Distributive Property Kya Hai? 🧱

βœ… Pehle Yeh Aata Hai?

Yeh post shuru karne se pehle, in teen sawaalon ko 1 minute mein khud try kijiye:

  1. 5 Γ— 10 = ?
  2. Like terms kya hote?
  3. a Γ— a ko kaise likhte?
Answers dekho
  1. 50
  2. Same letter-numbers wale (3x, 5x)
  3. aΒ²

Teeno sahi? Badhiya, aage chaliye! Koi galat hua? Koi baat nahi, Book 1 Ch 2 (exponents) aur Ch 5 dekh lijiye.

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🎬 Kahani: Tiffin Ki Dukaan Ka Hisaab

Sonu ki maa tiffin service chalaati hain. Har tiffin mein 6 roti aur 4 sabzi-katori. Aaj 5 tiffin bane. Sonu ne gina: β€œ6 + 4 = 10 cheezein, 10 Γ— 5 = 50.” 🍱

Maa ne alag gina: β€œRoti 5 Γ— 6 = 30, katori 5 Γ— 4 = 20, kul 50.” Dono ka jawab same!

Kya yeh sanyog hai? Nahi, yahi hai distributive property: guna ko tukdon mein baant do, phir jodo. Aaj iska β€œkyun” chitra se samjhenge. 🧠

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πŸ“– Concept: Guna = Area; Area Ko Tukdon Mein Baanto

πŸ’‘ Is post ki ek badi baat: a Γ— (b + c) ek rectangle ka area hai jiski chaudaai (b + c). Use do tukdon mein kaato: a Γ— b aur a Γ— c. Tukdon ka jod = poora area. Isliye a(b + c) = ab + ac, har number ke liye. Poora chapter isi ek idea pe khada hai.

Step 1: Chitra: dots ya area

5 panktiyon aur 6 + 4 kholon wala rectangle, do hisson mein: 5 Γ— 6 = 30 aur 5 Γ— 4 = 20, kul 50ab = 30ac = 20a = 5b = 6c = 4
5 panktiyon aur 6 + 4 kholon wala rectangle, do hisson mein: 5 Γ— 6 = 30 aur 5 Γ— 4 = 20, kul 50

5 panktiyaan, 6 + 4 = 10 khol. Poora: 5 Γ— 10 = 50. Tukde: 30 + 20 = 50 βœ…

WHY kaam karta? Rectangle kaatne se koi dot gayab nahi hota, na naya aata. Bas do baar mein gine.

Step 2: Ghataav pe bhi: a(b βˆ’ c) = ab βˆ’ ac

7 Γ— 48 = 7 Γ— (50 βˆ’ 2) = 350 βˆ’ 14 = 336.

WHY? 50 khol ka rectangle banao, phir 2 khol ka tukda hata do. Hataaya hua area = 7 Γ— 2.

Step 3: Ulta bhi: (a + b)c = ac + bc

(a + b)c = c(a + b) (guna ka kram badal sakte) = ca + cb = ac + bc.

Rectangle ko khada kaato ya leta, baat ek hi.

Step 4: Bracket mein kai terms

4a(3a βˆ’ 2b + 5) = 4a Γ— 3a βˆ’ 4a Γ— 2b + 4a Γ— 5 = 12aΒ² βˆ’ 8ab + 20a.

Har term ko bahar wale se guna karo, sign ke saath. Phir dekho: koi like terms? Yahan nahi (aΒ², ab, a sab alag).

Step 5: Ulta chalna: common nikaalo (factor)

6x + 9y = 3(2x + 3y). Distributive ko ulta padha: dono terms mein 3 common.

Kab kaunsa? Hisaab aasaan karna ho to kholo (7 Γ— 48). Expression chhota karna ho ya divisibility dikhani ho to common nikaalo (Ch 5 ka 6a + 6b = 6(a + b) yaad?).

πŸͺœ Atak Gaye? Aise Socho

  • Bracket ke bahar wala number/letter pehchaano.
  • Andar ke har term pe ek-ek teer banao.
  • Har teer pe guna karo, sign saath le jaao.
  • Like terms jodo.
  • Ek chhoti value (a = 1, b = 2) daal ke dono taraf check karo.

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πŸ” Deep Concept: Distributive: Jod Aur Guna Ka Pul

Jod aur guna do alag operation hain. Distributive property batati hai woh aapas mein kaise milte: guna, jod ke upar β€œbaant” jaata hai.

Par ulta nahi! Jod guna pe nahi baant-ta: 2 + (3 Γ— 4) = 14, par (2 + 3) Γ— (2 + 4) = 30 βœ—. Aur guna guna pe bhi nahi: 2 Γ— (3 Γ— 4) = 24, par (2 Γ— 3) Γ— (2 Γ— 4) = 48 βœ—.

Itihaas: Brahmagupta (628 CE) ne BrāhmasphuαΉ­asiddhānta mein ise khaṇḍa-guαΉ‡anam (tukdon mein guna) kaha: β€œGuna karne wale ko tukdon mein todo jinka jod wahi ho, har tukde se guna karo, aur jodo.” Euclid ne isse geometry mein, Aryabhata ne algebra mein istemaal kiya.

Unifying idea: mushkil guna = aasaan tukde. Aage ke saare identities, (a + b)², fast multiplication, sab isi ek pul pe chalte hain. 🎯

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✏️ Solved Examples

Example 1 (Easy): 9 Γ— 104 mann mein.

9 Γ— (100 + 4) = 900 + 36 = 936.

Check: 936 Γ· 9 = 104 βœ…

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Example 2 (Medium): βˆ’3p(2p βˆ’ 5q + 1) kholo.

βˆ’3p Γ— 2p = βˆ’6pΒ², βˆ’3p Γ— (βˆ’5q) = +15pq, βˆ’3p Γ— 1 = βˆ’3p β†’ βˆ’6pΒ² + 15pq βˆ’ 3p.

Check: p = 1, q = 1: baayan βˆ’3(2 βˆ’ 5 + 1) = 6; daayan βˆ’6 + 15 βˆ’ 3 = 6 βœ…

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Example 3 (NCERT style): 17 Γ— 6 + 17 Γ— 4 sabse aasaan tareeke se.

Ulta distributive: 17 Γ— (6 + 4) = 17 Γ— 10 = 170.

Check: 102 + 68 = 170 βœ…

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Sonu aur maa: dono sahi the. Sonu ne poora rectangle gina (5 Γ— 10), maa ne tukde (30 + 20). Agle din 12 tiffin: maa ne turant kaha β€œ72 roti, 48 katori, 120 cheezein”! 🍱

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🏠 Distributive Property Roz Ki Zindagi Mein

  • πŸ›’ Shopping: 4 kilo seb β‚Ή98 kilo: 4 Γ— 100 βˆ’ 4 Γ— 2 = β‚Ή392.
  • πŸŽ’ School kit: 30 bachche, har ek ko 2 copy + 1 pen: 30 Γ— 2 + 30 Γ— 1 = 90 cheezein.
  • 🏠 Ghar ka farsh: L-shape kamra = do rectangles ke area ka jod.
  • 🍬 Mithai ke dabbe: 8 dabbe, har ek mein 12 laddoo + 6 barfi = 8 Γ— 18 = 144.
  • πŸ’° Salary: 25 din Γ— (β‚Ή400 + β‚Ή50 bonus) = 25 Γ— 400 + 25 Γ— 50.

Dukaandaar roz yeh karte: β€œβ‚Ή99 Γ— 6? 600 βˆ’ 6 = β‚Ή594!” Distributive = mental maths ka superpower. πŸ’ͺ

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🧭 Kab Use Karein, Kab Nahi

SituationKya kareinKyun
Hisaab aasaan karnaβœ… Kholo (7 Γ— 48 = 7 Γ— 50 βˆ’ 7 Γ— 2)Paas ka gol number
Expression chhota karnaβœ… Common nikaaloUlta distributive
Kai terms bracket meinβœ… Har term ko gunaSign dhyaan
Jod guna pe?❌ Nahi baant-ta2 + 3 Γ— 4
Guna guna pe?❌ Nahi2(3 Γ— 4) β‰  6 Γ— 8

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βŒβ†’βœ… Worked Mistake

Sawaal: 5(2x + 3) kholo.

❌ Galat: 10x + 3. Sirf pehle term ko guna kiya!

βœ… Sahi: 5 Γ— 2x + 5 Γ— 3 = 10x + 15. Check: x = 1: 5 Γ— 5 = 25; 10 + 15 = 25 βœ…

Doosri common galti: βˆ’2(a βˆ’ 3) = βˆ’2a βˆ’ 6. Sign! βˆ’2 Γ— (βˆ’3) = +6 β†’ βˆ’2a + 6.

🧠 Rule of thumb: Bahar wala andar ke HAR term se milta hai, sign ke saath.

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πŸ“ 10 MCQs

Q1. 6(a + 7) = ?

(a) 6a + 7
(b) 6a + 42
(c) a + 42
(d) 13a
Solution dekho

Sahi jawab: (b)

  • (a) galat: 7 ko bhi 6 se guna karna tha.
  • (b) sahi: 6 Γ— a + 6 Γ— 7 = 6a + 42 βœ…
  • (c) galat: a ko bhi 6 se guna karna tha.
  • (d) galat: 6 aur 7 jodna galat hai.

Q2. 8 Γ— 97 aasaan tareeke se?

(a) 800 βˆ’ 24
(b) 800 βˆ’ 3
(c) 720 + 7
(d) 8 Γ— 100 + 3
Solution dekho

Sahi jawab: (a)

  • (a) sahi: 8 Γ— (100 βˆ’ 3) = 800 βˆ’ 24 βœ…
  • (b) galat: 3 ko bhi 8 se guna karna tha.
  • (c) galat: Yeh tukde 97 nahi banaate.
  • (d) galat: 97 = 100 βˆ’ 3, plus nahi.

Q3. βˆ’4(x βˆ’ 2) = ?

(a) βˆ’4x βˆ’ 8
(b) βˆ’4x + 8
(c) 4x βˆ’ 8
(d) βˆ’4x βˆ’ 2
Solution dekho

Sahi jawab: (b)

  • (a) galat: βˆ’4 Γ— βˆ’2 = +8, minus nahi.
  • (b) sahi: βˆ’4 Γ— βˆ’2 = +8, to βˆ’4x + 8 βœ…
  • (c) galat: x ka sign ulta ho gaya.
  • (d) galat: 2 ko bhi βˆ’4 se guna karna tha.

Q4. 2a(3a + b) = ?

(a) 6a + 2ab
(b) 6aΒ² + 2ab
(c) 5aΒ² + 2ab
(d) 6aΒ² + b
Solution dekho

Sahi jawab: (b)

  • (a) galat: 2a Γ— 3a = 6aΒ², sirf 6a nahi.
  • (b) sahi: Sahi jawab: 2a Γ— 3a + 2a Γ— b βœ…
  • (c) galat: 2 Γ— 3 = 6, jod nahi, isliye yeh galat.
  • (d) galat: b ko bhi 2a se guna karna tha.

Q5. 12x + 18 = ?

(a) 6(2x + 3)
(b) 6(2x + 18)
(c) 3(4x + 18)
(d) 12(x + 18)
Solution dekho

Sahi jawab: (a)

  • (a) sahi: Sahi jawab: Common 6 nikaala βœ…
  • (b) galat: 18 Γ· 6 = 3 hona chahiye.
  • (c) galat: 18 Γ· 3 = 6 hona chahiye.
  • (d) galat: 18 Γ· 12 = 18 nahi hota.

Q6. 2 + (3 Γ— 4) = (2 + 3)(2 + 4)?

(a) Haan
(b) Nahi
(c) Kabhi-kabhi
(d) Sirf integers
Solution dekho

Sahi jawab: (b)

  • (a) galat: 14 aur 30 alag hain, isliye yeh galat.
  • (b) sahi: Jod guna pe nahi baant-ta βœ…
  • (c) galat: Yahan to bilkul nahi, isliye yeh galat.
  • (d) galat: Integers mein bhi nahi.

Q7. Khaṇḍa-guαΉ‡anam kisne likha?

(a) Brahmagupta
(b) Euclid
(c) Newton
(d) Pascal
Solution dekho

Sahi jawab: (a)

  • (a) sahi: BrāhmasphuαΉ­asiddhānta (628 CE) βœ…
  • (b) galat: Euclid ne geometry mein use kiya.
  • (c) galat: Newton bahut baad mein aaye.
  • (d) galat: Pascal ka yeh kaam nahi tha.

Q8. 23 Γ— 7 + 23 Γ— 3?

(a) 230
(b) 161
(c) 69
(d) 253
Solution dekho

Sahi jawab: (a)

  • (a) sahi: Sahi jawab: 23 Γ— (7 + 3) = 230 βœ…
  • (b) galat: 161 sirf 23 Γ— 7 hai, isliye yeh galat.
  • (c) galat: 69 sirf 23 Γ— 3 hai, isliye yeh galat.
  • (d) galat: 253 = 23 Γ— 11 hota, 23 Γ— 10 nahi.

Q9. 3(2x βˆ’ y + 4) mein y ka term?

(a) βˆ’3y
(b) βˆ’y
(c) 3y
(d) βˆ’3
Solution dekho

Sahi jawab: (a)

  • (a) sahi: Sahi jawab: 3 Γ— (βˆ’y) = βˆ’3y βœ…
  • (b) galat: y ko bhi 3 se guna karna tha.
  • (c) galat: Sign minus hai, plus nahi.
  • (d) galat: Letter y bhi chahiye, isliye yeh galat.

Q10. Rectangle 5 Γ— (6 + 4) ke tukde?

(a) 30 + 20
(b) 11 + 9
(c) 30 + 4
(d) 5 + 10
Solution dekho

Sahi jawab: (a)

  • (a) sahi: Sahi jawab: 5 Γ— 6 aur 5 Γ— 4 βœ…
  • (b) galat: Yeh jod hain, guna nahi.
  • (c) galat: 4 ko bhi 5 se guna karna tha.
  • (d) galat: Yeh area nahi, lambaai hai.

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❓ FAQs (Bachchon Ke Asli Sawaal)

1. Distributive property ka naam kyun?

Bahar ka guna andar ke har term pe β€œbaant” (distribute) diya jaata hai.

2. Kya negative numbers pe bhi?

Haan: x(y + z) = xy + xz sab integers (aur fractions) pe sach.

3. Bhaag pe?

(a + b) Γ· c = a Γ· c + b Γ· c sach. Par c Γ· (a + b) β‰  c Γ· a + c Γ· b.

4. Identity kya hai?

Aisi barabari jo letters ki har value pe sach ho, jaise a(b + c) = ab + ac.

5. Chitra kyun zaroori?

Chitra se β€œkyun” dikhta: area tukdon mein baant-ta hai. Formula bhool jao, chitra yaad rahega.

6. Aage kya?

Do brackets ka guna (a + m)(b + n): Post 2 β€” Guna Mein Badlaav: Increments.

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πŸ‹οΈ Practice Zone (12 Sawaal)

Q1. Easy 7(x + 5) kholo.

Solution dekho

7x + 35. Check: x = 1 β†’ 42 βœ…

Q2. Easy 6 Γ— 103 mann mein.

Solution dekho

600 + 18 = 618. Check βœ…

Q3. Easy 15a + 20 mein common nikaalo.

Solution dekho

5(3a + 4). Check: a = 1 β†’ 35 βœ…

Q4. Easy 9 Γ— 49?

Solution dekho

450 βˆ’ 9 = 441. Check: 21Β² = 441 βœ…

Q5. Medium βˆ’5(2y βˆ’ 3) kholo.

Solution dekho

βˆ’10y + 15. Check: y = 1 β†’ 5 βœ…

Q6. Medium 3x(x βˆ’ 4y + 2) kholo.

Solution dekho

3xΒ² βˆ’ 12xy + 6x. Check: x = 1, y = 1 β†’ βˆ’3 βœ…

Q7. Medium 46 Γ— 25 + 54 Γ— 25?

Solution dekho

25 Γ— 100 = 2500. Check βœ…

Q8. Medium 2(3a + 1) + 4(a βˆ’ 2) saral karo.

Solution dekho

6a + 2 + 4a βˆ’ 8 = 10a βˆ’ 6. Check: a = 1 β†’ 4 βœ…

Q9. NCERT style (2/3)(9a βˆ’ 6b + 12) kholo.

Solution dekho

6a βˆ’ 4b + 8. Check: a = b = 1 β†’ 10 βœ…

Q10. NCERT style 999 Γ— 7 mann mein.

Solution dekho

7000 βˆ’ 7 = 6993. Check βœ…

Q11. NCERT style a(b βˆ’ c) + b(c βˆ’ a) + c(a βˆ’ b) = ?

Solution dekho

Sab kat jaata β†’ 0. Check: a = 1, b = 2, c = 3 β†’ βˆ’1 + 4 βˆ’ 3 = 0 βœ…

Q12. NCERT style xΒ² + 5x mein common nikaalo.

Solution dekho

x(x + 5). Check: x = 2 β†’ 14 βœ…

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🧠 HOTS (Sochne Wale Sawaal)

Q1. Kya (a + b) Γ· c = a Γ· c + b Γ· c? Aur c Γ· (a + b)?

Solution dekho

Pehla haan, doosra nahi: 12 Γ· (2 + 4) = 2, par 6 + 3 = 9. Check βœ…

Q2. L-shape: 8 Γ— 10 ka rectangle jisme 3 Γ— 4 ka kona kata. Area do tareeke se?

Solution dekho

80 βˆ’ 12 = 68; ya tukde 8 Γ— 6 + 5 Γ— 4 = 48 + 20 = 68. Check βœ…

Q3. n(n + 1) βˆ’ n(n βˆ’ 1) = ?

Solution dekho

nΒ² + n βˆ’ nΒ² + n = 2n. Check: n = 3 β†’ 12 βˆ’ 6 = 6 βœ…

Q4. Kya distributive se dikhao ki 3 lagaataar numbers ka jod 3 ka multiple?

Solution dekho

(n βˆ’ 1) + n + (n + 1) = 3n = 3 Γ— n. Check: 4 + 5 + 6 = 15 βœ…

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πŸ† Olympiad Corner

Q1. 37 Γ— 27 + 37 Γ— 73?

Solution dekho

3700.

Q2. 125 Γ— 32 mann mein?

Solution dekho

125 Γ— 8 Γ— 4 = 4000.

Q3. a = 2, b = 3: 4a(b βˆ’ a) + 2b(a + b)?

Solution dekho

8 + 30 = 38.

Q4. 9999 Γ— 12?

Solution dekho

119988.

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πŸ’— CharuMam Motivation

Sonu ne seekha: ek hi cheez ko do tarah se ginna, aur dono ka same aana: yahi maths ki khoobsurti hai. Aage har identity isi se niklegi! 🌟

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🟒 Master Recap

  • πŸ’‘ Chaabi: a Γ— (b + c) ek rectangle ka area hai jiski chaudaai (b + c). Use do tukdon mein kaato: a Γ— b aur a Γ— c. Tukdon ka jod = poora area. Isliye a(b + c) = ab + ac, har number ke liye. Poora chapter isi ek idea pe khada hai.
  • a(b + c) = ab + ac (area ka chitra).
  • a(b βˆ’ c) = ab βˆ’ ac.
  • Bracket ke har term ko guna, sign ke saath.
  • Ulta: common nikaalo.
  • Jod guna pe nahi baant-ta.
  • Brahmagupta: khaṇḍa-guαΉ‡anam.

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